answer the following questions?
if 2x+3y=26,xy=2 find the value of
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Answer is here:
So squaring on both sides.
(2x + 3y)^2 = (26)^2
(2x)^2 + (3y) + 2*2x*3y = 676
4x^2 + 9y^2 + 12xy = 676
4x^2 + 9y^2 + 12*2 = 676
4x^2 + 9y^2 + 24 = 676
4x^2 + 9y^2 = 676 - 24
4x^2 + 9y^2= 652
So squaring on both sides.
(2x + 3y)^2 = (26)^2
(2x)^2 + (3y) + 2*2x*3y = 676
4x^2 + 9y^2 + 12xy = 676
4x^2 + 9y^2 + 12*2 = 676
4x^2 + 9y^2 + 24 = 676
4x^2 + 9y^2 = 676 - 24
4x^2 + 9y^2= 652
badalmohanty06p6epf9:
hm.....re bat karini hai
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here is ur answer
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