Question

●Answer the given attachment

No Spam!!
​

Answer 1

Answer:

$\begin{gathered}\Large{\textbf{\textsf{\underline{\underline{\color{purple}{Question:-}}}}}}\end{gathered}$

★ Complete The Last Column of the table.

$\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\boxed{\begin{array}{c|c|c|c}\bf{S.No.}&\bf \: {Equation}&\bf \:{Value}& \bf{(Yes | No)}\\\frac{\qquad \qquad}{}&\frac{\qquad \qquad}{}&\frac{\qquad \qquad}{}&\frac{\qquad \qquad}{}\\\sf {1)}&\sf{x + 3 = 0}&\sf{x = 3}& \sf{}\\\\\sf{2)}&\sf x + 3 = 0&\sf x = 0&\sf \\\\\sf 3)&\sf x + 3 = 0&\sf x = - 3&\sf \\\\\sf 4)&\sf x - 7&\sf x = 7&\sf \\\\\sf 5)&\sf x - 7&\sf x = 8&\sf \\\\\sf 6)&\sf 5x = 25&\sf x = 0&\sf \\\\\sf 7)&\sf 5x = 25&\sf x = 5&\sf \\\\ \sf 8)&\sf 5x = 25&\sf x = - 5&\sf \\\\ \sf 9)&\sf \dfrac{m}{3} = 2&\sf m = - 6&\sf \\\\ \sf 10)&\sf \dfrac{m}{3} = 2 &\sf m = 0&\sf \\\\ \sf 11)&\sf \dfrac{m}{3} = 2 &\sf m = 6&\sf \\\\ \end{array}}\end{gathered}\end{gathered}\end{gathered}\end{gathered}$

$\begin{gathered}\end{gathered}$

$\begin{gathered}\Large{\textbf{\textsf{\underline{\underline{\color{purple}{Solution:-}}}}}}\end{gathered}$

$\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\boxed{\begin{array}{c|c|c|c}\bf{S.No.}&\bf \: {Equation}&\bf \:{Value}& \bf{(Yes | No)}\\\frac{\qquad \qquad}{}&\frac{\qquad \qquad}{}&\frac{\qquad \qquad}{}&\frac{\qquad \qquad}{}\\\sf {1)}&\sf{x + 3 = 0}&\sf{x = 3}& \sf{yes}\\\\\sf{2)}&\sf x + 3 = 0&\sf x = 0&\sf no\\\\\sf 3)&\sf x + 3 = 0&\sf x = - 3&\sf no\\\\\sf 4)&\sf x - 7&\sf x = 7&\sf no \\\\\sf 5)&\sf x - 7&\sf x = 8&\sf yes\\\\\sf 6)&\sf 5x = 25&\sf x = 0&\sf no\\\\\sf 7)&\sf 5x = 25&\sf x = 5&\sf yes \\\\ \sf 8)&\sf 5x = 25&\sf x = - 5&\sf no \\\\ \sf 9)&\sf \dfrac{m}{3} = 2&\sf m = - 6&\sf no \\\\ \sf 10)&\sf \dfrac{m}{3} = 2 &\sf m = 0&\sf no \\\\ \sf 11)&\sf \dfrac{m}{3} = 2 &\sf m = 6&\sf yes \\\\ \end{array}}\end{gathered}\end{gathered}\end{gathered}\end{gathered} \\\\\dag{\bf{\underline{\red{LoveYouHindi}}}}$

$\begin{gathered}\end{gathered}$

★ 1st Statement

$: \implies \sf{(x + 3 = 0)} = (x = 3)$

$: \implies \sf{(x = 0 - 3)} = (x = 3)$

$: \implies \sf{(x =- 3)} = (x = 3)$

• The Answer is No.

$\begin{gathered}\end{gathered}$

★ 2nd Statement

$: \implies \sf{(x + 3 = 0)} = (x = 0)$

$: \implies \sf{(x = 0 - 3)} = (x = 0)$

$: \implies \sf{(x = - 3)} = (x = 0)$

• The Answer is No.

$\begin{gathered}\end{gathered}$

★ 3rd Statement

$: \implies \sf{(x + 3 =0 )} = (x = - 3)$

$: \implies \sf{(x =0 - 3 )} = (x = - 3)$

$: \implies \sf{(x =- 3 )} = (x = - 3)$

• The Answer is Yes.

$\begin{gathered}\end{gathered}$

★ 4th Statement

$: \implies \sf{(x - 7=1 )} = (x = 7)$

$: \implies \sf{(x =1 + 7 )} = (x = 7)$

$: \implies \sf{(x =8 )} = (x = 7)$

• The Answer is No.

$\begin{gathered}\end{gathered}$

★ 5th Statement

$: \implies \sf{(x - 7=1 )} = (x = 8)$

$: \implies \sf{(x =1 +7 )} = (x = 8)$

$: \implies \sf{(x =8 )} = (x = 8)$

• The Answer is Yes.

$\begin{gathered}\end{gathered}$

★ 6th Statement

$: \implies\sf(5x = 25) = ( x=0)$

$: \implies\sf \bigg(x = \dfrac{25}{5}\bigg) = ( x=0)$

$: \implies\sf \bigg(x = \cancel\dfrac{25}{5}\bigg) = ( x=0)$

$: \implies\sf {(x = 5) = ( x=0)}$

• The Answer is No.

$\begin{gathered}\end{gathered}$

★ 7th Statement

$: \implies\sf(5x = 25) = ( x=5)$

$: \implies\sf \bigg(x =\dfrac{25}{5}\bigg) = ( x=5)$

$: \implies\sf \bigg(x = \cancel\dfrac{25}{5}\bigg) = ( x=5)$

$: \implies\sf {(x = 5) = ( x=5)}$

• The Answer is Yes.

$\begin{gathered}\end{gathered}$

★ 8th Statement

$: \implies\sf(5x = 25) = ( x= - 5)$

$: \implies\sf \bigg(x = \dfrac{25}{5}\bigg) = ( x= - 5)$

$: \implies\sf \bigg(x = \cancel\dfrac{25}{5}\bigg) = ( x= - 5)$

$: \implies\sf {(x = 5) = ( x= - 5)}$

• The Answer is No.

$\begin{gathered}\end{gathered}$

★ 9th Statement

$: \implies\sf{\bigg(\dfrac{m}{3} = 2 \bigg) = (m = - 6)}$

$: \implies\sf{({m} = 2 \times 3 )= (m = - 6)}$

$: \implies\sf{({m} = 6 )= (m = - 6)}$

• The Answer is No.

$\begin{gathered}\end{gathered}$

★ 10th Statement

$: \implies\sf{\bigg(\dfrac{m}{3} = 2 \bigg) = (m = 0)}$

$: \implies\sf{({m} = 2 \times 3 )= (m = 0)}$

$: \implies\sf{({m} = 6 )= (m = 0)}$

• The Answer is No.

$\begin{gathered}\end{gathered}$

★ 11th Statement

$: \implies\sf{\bigg(\dfrac{m}{3} = 2 \bigg) = (m = 6)}$

$: \implies\sf{({m} = 2 \times 3 )= (m = 6)}$

$: \implies\sf{({m} = 6 )= (m = 6)}$

• The Answer is Yes.