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Let no. of 10p coins be x and no. of 50p coins be y
Given ,
no.of coins = x + y = 70 ---------(1)
value = 10x + 50y = 1900p --------(2)
(1) × 10 --------> 10x + 10y = 700
(1) - (2) ----------> 10x + 10y =700
-10x - 50y= -1900
======> - 40y = -1200
y = 30
x = 70- y
= 40
therefore no. of 10p coins = 40
no. of 50p = 30
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