Answer the given Riddle...
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Answered by
5
Hello!
Let's stars be x , fan be y and clocks be z
Then according to first equation ,
x + x + x = 18......(1)
3x = 18
x = 6
So, Stars are 6.
y + y + x = 14.......(2)
2y + 6 = 14
2y = 8
y = 4
So, for fan no. is 4
z + z - y = 2
2z - 4 = 2
2z = 6
z = 3
So, for clock no. will be 3
Now ,
y + z × 2(x) = ?
4 + 3 × 2(6) = 40
So, required Answer is 40.
Thanks:)
Let's stars be x , fan be y and clocks be z
Then according to first equation ,
x + x + x = 18......(1)
3x = 18
x = 6
So, Stars are 6.
y + y + x = 14.......(2)
2y + 6 = 14
2y = 8
y = 4
So, for fan no. is 4
z + z - y = 2
2z - 4 = 2
2z = 6
z = 3
So, for clock no. will be 3
Now ,
y + z × 2(x) = ?
4 + 3 × 2(6) = 40
So, required Answer is 40.
Thanks:)
ABHAYSTAR:
Thank you :)
Answered by
1
WE NEED TO OBSERVE THE GIVEN SHAPES AND WHAT THE OBJECTS INDICATE AND THEN FIND THE VALUES.
firstly the stars have 6 triangular shapes with each star so let the six traingled star value be 6.
3(6) = 18.
here the stars value is 6.
next the fans have four wings so its value is 4.
so 2(4)+6= 14
next theres that clock in which its 3'o clock so its value is 3.
2(3)-4=02.
and at last a 3 winged fan value=3.
a clock of 2'o clock value=2
and two stars of 5 triangle shapes= 2(5)=10.
so 3+2x10 = 23.
23 IS THE ANSWER OF THE QUESTION.
firstly the stars have 6 triangular shapes with each star so let the six traingled star value be 6.
3(6) = 18.
here the stars value is 6.
next the fans have four wings so its value is 4.
so 2(4)+6= 14
next theres that clock in which its 3'o clock so its value is 3.
2(3)-4=02.
and at last a 3 winged fan value=3.
a clock of 2'o clock value=2
and two stars of 5 triangle shapes= 2(5)=10.
so 3+2x10 = 23.
23 IS THE ANSWER OF THE QUESTION.
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