Question

answer the question???​

Answer 1

$\underline{ \boxed{ \bold{ \mathfrak{ \huge{ \purple{Answer}}}}}}$

Given :

no. of electron move out of a body in a second = 10^9

To Find :

Time requires to get a total charge of 1C on the other body...

Formula :

Formula of charge in terms of no. of electron is given by...

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \dag \: \underline{ \boxed{ \bold{ \rm{ \pink{q = ne}}}}} \: \dagger$

Calculation :

$\implies \rm \: 1 = n \times 1.6 \times {10}^{ - 19} \\ \\ \therefore \rm \: n = \frac{1}{1.6} \times {10}^{19} \\ \\ \implies \rm \: time \: requires = \frac{ {10}^{19} }{1.6 \times {10}^{9} } = \frac{1}{1.6} \times {10}^{10} \\ \\ \therefore \: \boxed{\red{ \rm{t = 6.25 \times {10}^{9} \: s}}}$

Answer 2

$\huge \fcolorbox{red}{pink}{Solution :)}$

Given ,

The number of electrons move out of a body to another body in 1 sec is (10)^9

We know that , the relationship between electron and charge is given by

$\large \sf \fbox{q = n \times e}$

Thus , the charge given out in 1 sec is

$\sf \hookrightarrow q \: (in \: 1 \: sec) \: = {(10)}^{9} \times 1.6 \times {(10)}^{ - 19} \\ \\ \sf \hookrightarrow q \: (in \: 1 \: sec) \: = 1.6 \times {(10)}^{- 10} \: \: coulomb$

Therefore , the total time required to given out a 1 coulomb charge is

$\sf \hookrightarrow Time = \frac{1}{1.6 \times {(10)}^{ - 11} } \\ \\\sf \hookrightarrow Time = \frac{1 \times {(10)}^{ 11} \times {(10)}^{1} }{16} \\ \\\sf \hookrightarrow Time = 0.0625 \times {(10)}^{12} \\ \\\sf \hookrightarrow Time = 6.25 \times {(10)}^{9} \: \: sec$

Hence , 6.25 × (10)^9 sec is required to given out a 1 C charge

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