Question

answer the question ✔✔✔​

Answer 1

Given :-

• A trapezium whose area is 105cm square and bases are 14cm and 7cm.

To find :-

• Altitude of trapezium

Solution :-

• Area of trapezium = 105 cm²

• Bases of trapezium = 14cm and 7cm

As we know that

• → Area of trapezium = ½ (a + b) × h

• Where " (a + b) " is sum of parallel sides and " h " is Altitude.

According to the question

• → Bases of trapezium = parallel sides

• → Area of trapezium = 105 cm²

• → ½ (a + b) × h = 105

• → ½ (14 + 7) × h = 105

• → ½ × 21 × h = 105

• → 21/2 × h = 105

• → h = 105 × 2/21

• → h = 10 cm

Therefore,

• Height of trapezium is 10cm

More to know :-

• Area of circle = πr²

• Circumference of circle = 2πr

• Perimeter of rectangle =2(l + b)

• Perimeter of square = 4 × side

• Area of square = side × side

• Area of rhombus = ½ × product of diagonals

• Area of Parallelogram = base × height

Answer 2

Answer:

10cm

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