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p(x) = (x+1) = 0
x = (-1)
Let's substitute the value of x in the given equation,
⇒ x^3-5x²+x-5
⇒ (-1)^3-5(-1)²+(-1)-5
⇒ -1+5-1+5
⇒ 10-2
⇒ 8
Therefore, the remainder is 8
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