Math, asked by jpatar16, 1 year ago

answer the question

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Answered by sprao534
1
Please see the attachment
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jpatar16: thank you
Answered by anupamchaudhury12
2

LHS

= 1/ sin 10 - √3 / cos 10

= (cos 10 - √3 sin 10)/ sin 10 cos 10

= 2 (cos 10 - √3 sin 10)/ 2 sin 10 cos 10      [multiplied and divided by 2]

=  2 (1/2 cos 10 - √3/2 sin 10)/  sin 10 cos 10

= 2 x 2 (sin 30 cos 10 - cos 30 sin 10) / 2 sin 10 cos 10    [multiplied and divided by 2]

= 4 { sin (30-10)}/ sin (2x10)      [sin (a+b = sin a cos b + cos a sin b)]  [ sin 2a = 2 sin a cos a]

= 4 (sin 20)/sin 20

= 4

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