Math, asked by jpatar16, 1 year ago

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Answered by roja34
1
sin²A=1-cos²a

sin (a+b) = sinA.cosB-cosA.sinB

sin (a-b) = sinA.cosB+cosA.sinB

so,,
sin(A+B) sin (A-B)

(sinA.cosB-cosA.sinB) (sinA.cosB+cosA.sinB)

(sinAcosB)² - (cosA.sinB)²

sin²A cos²B - cos²A. sinB²

(1-cos²A) cos²B - cos²A (1-cos²B)

cos²B - cos²A cos²B - cos²A + cos²A cos²B

= cos²B - cos²A.

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