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x+iy = √(a+ib)÷(c+id)
it's conjugate
(x±iy = √(a±ib) ÷ ( c±id)
(x+iy) (x-iy) = √(a+ib) (a-ib) ÷ (c+id) (c-id)
(x²+y²) = √(a²+b²)÷√(c²+d²)
(x²+y²) = a²+b² ÷ c²+d².
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it's conjugate
(x±iy = √(a±ib) ÷ ( c±id)
(x+iy) (x-iy) = √(a+ib) (a-ib) ÷ (c+id) (c-id)
(x²+y²) = √(a²+b²)÷√(c²+d²)
(x²+y²) = a²+b² ÷ c²+d².
plzz mark as brainliest.
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