Math, asked by nishikanisha44, 3 months ago

answer the question and explain​

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Answered by arnavvats2020
0

Answer:

Usage of Iron everyday = 1000W

Per day = 1000 x 1/2( 1 hour = 60 m , 30 m = 1/2 hours)

=> 500W

Usage of Geyser everyday = 2000W

Per day = 2000 x 1

=> 2000

Usage of 7 bulb  everyday = 100W

Per day = 100 x 3

=> 300W

Every day's usage = 500 + 2000 + 300

Total => 2800 W per day

1 kw = 1000w

2800 W = 2.8KW per day

Month reading = 3.1(In Kw) (reading of first day) + 2.8 x 29 ( Power usage of first day is given)( June has 30 days)

Total monthly => 84.3 KW

1kw = unit

Cost of 1 unit = 4 rupees

Monthly Cost = 4 x 84.3

=> 337.2 Rupees

Approx. -> 337 rupees

Answered by sankhalashankerlal
0

Answer:

which is this question I don't no

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