Question

Answer the question attached asap !!







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Answer 1

This dilution problem uses the equation

$M_aV_b=M_bV_b$

$M_a$= 3.0M - the initial molarity (concentration)

$V_a$= 100 mL - the initial volume

$M_b$= 1.25 M - the desired molarity (concentration)

$V_b$= (100mL + x ) - the volume of thedesired solution

$(3.0M)(100mL)=(1.25M)(100mL+x) \\ 300M \:mL=1.25M\left(100mL+x\right) \\ 300M \: mL=125M \: mL+1.25x \\ 125M \: mL+1.25x=300M \: mL \\ 1.25x\: mL=300M \: mL-125M \: mL \\ 1.25x \: mL=175 M \: mL \\ x=\frac{175M \: mL}{1.25mL} \\ \\x=\frac{17500M \: mL}{125mL} \\ \\ x=140 mL$

59.7 mL needs to be added to the original 15.00 mL solution in order to dilute it from 6.77 M to 1.50 M.

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ummmmmmmmmmmmmm,i dun if it's correct or not! but i hope it helps uh a lilu! (٥↼_↼)

U r my senior,me High school stupad, so me dun know about this high class sheet! plj, Adjust with answer!

Answer 2

Answer:

hola amigo

lmao this was probably properly answered

Step-by-step explanation:

which is this language tho????