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(cosA-sinA+1)/(cosA+sinA-1) = cosecA+cotA
L. H. S =
Diving by sinA in numerator, we get
(cotA-1+cosecA)/(cotA+1-cosecA)
cotA+cosecA-1 / (cotA-cosecA+1)
cotA+cosecA-(cosec²A-cot²A)/(cotA-cosecA+1)
cotA+cosecA-[(cosecA+cotA)(cosecA-cotA)] / (cotA-cosecA+1)
Taking common cosecA+cotA in numerator, we get
cosecA+cotA [(1-cosecA +cotA)] /(cotA-cosecA+1)
cosecA+cotA [(1-cosecA+cotA)] /(1-cosecA+cotA)
Hence, (1-cosecA+cotA) will be canceled in numerator and denomination and Answer will be cosecA +cotA.
Thanks!
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