answer the question fast
Attachments:
Answers
Answered by
1
focal length = -20 cm
height of object, h= +6 cm
image distance = -15 cm
by lens formula,
1/v - 1/u = 1/f
⇒ 1/-15 - 1/u = 1/-20
⇒1/u = 1/-15 - 1/-20 = -3+2 / 60 = -1/60
⇒ u = -60 cm
so the object should be placed 60 cm in front of the lens.
we know that,
magnification = v/u = h'/h
⇒ -15/-60 = h'/6
⇒ h'= 6/3 = 2 cm
so, the image will be 2 cm in height
height of object, h= +6 cm
image distance = -15 cm
by lens formula,
1/v - 1/u = 1/f
⇒ 1/-15 - 1/u = 1/-20
⇒1/u = 1/-15 - 1/-20 = -3+2 / 60 = -1/60
⇒ u = -60 cm
so the object should be placed 60 cm in front of the lens.
we know that,
magnification = v/u = h'/h
⇒ -15/-60 = h'/6
⇒ h'= 6/3 = 2 cm
so, the image will be 2 cm in height
Anonymous:
thank you
Answered by
1
hope it helps
plzz mark it as brainliest
plzz mark it as brainliest
Attachments:
Similar questions