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heya friend!!
here is your answer in the attachment...
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girishmehta72:
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HEllO friend ,
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Let P = 5 kg weight = 5 g Newtons
Q = 10 g Newtons
Using the parallelogram law of addition of vectors :
Resultant force magnitude = R
R² = P² + Q² + 2 P Q Cos Ф = 5² + 10² + 2 * 5 * 10 * Cos 120
= 125 - 50 = 75
R = 5√3 newtons
Angle made by R with Q = 10 kg weight = α
tan α = P Sin Ф / ( P + Q Cos Ф)
= 5 Sin 120 / (10 + 5 Cos 120) = 2.5 √3 / 7.5 = 1/√3
α = 30°
Hope it helps you
*************×************×*******×
Let P = 5 kg weight = 5 g Newtons
Q = 10 g Newtons
Using the parallelogram law of addition of vectors :
Resultant force magnitude = R
R² = P² + Q² + 2 P Q Cos Ф = 5² + 10² + 2 * 5 * 10 * Cos 120
= 125 - 50 = 75
R = 5√3 newtons
Angle made by R with Q = 10 kg weight = α
tan α = P Sin Ф / ( P + Q Cos Ф)
= 5 Sin 120 / (10 + 5 Cos 120) = 2.5 √3 / 7.5 = 1/√3
α = 30°
Hope it helps you
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