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t1=22
tn=-11
Sn=66
n/2(a+l)=66
n/2(22+(-11))=66
n/2(22-11)=66
n/2×11=66
11n=66×2
n=66×2/11
n=12.
tn=-11
Sn=66
n/2(a+l)=66
n/2(22+(-11))=66
n/2(22-11)=66
n/2×11=66
11n=66×2
n=66×2/11
n=12.
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Given
A=22,an=-11 &sn= 66
an=a+(n-1)d
-11=22+(n-1)d
(n-1)d=-33.…...(1)
Also,
sn=n/2[2a+(n-1)d]
66=n/2[2(22)+(n-1)d]
132=n[44+( n-1)d] ....(using 1)
132=n(11)
n=12
Also,on putting n=12 in 1 we get.
(12-1) d=-33
11d=-33
d=-3...
A=22,an=-11 &sn= 66
an=a+(n-1)d
-11=22+(n-1)d
(n-1)d=-33.…...(1)
Also,
sn=n/2[2a+(n-1)d]
66=n/2[2(22)+(n-1)d]
132=n[44+( n-1)d] ....(using 1)
132=n(11)
n=12
Also,on putting n=12 in 1 we get.
(12-1) d=-33
11d=-33
d=-3...
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