Question

Answer the question in the photo​

Answer 1

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Answer 2

Given :-

• log(x+y/3) = 1/2 * (logx + logy) .

To Prove :-

• x² + y² = 7xy ?

Formula used :-

• n log a = log a^n
• log a + log b = log(ab)

Solution :-

→ log(x+y/3) = 1/2 * (logx + logy)

→ 2*log(x+y/3) = (logx + logy)

→ log(x+y/3)² = (logx + logy)

→ log(x+y/3)² = log(x *y)

→ [ ( x + y ) / 3 ]² = xy

→ ( x + y )² / (3)² = xy

→ x² + y² + 2xy = 9xy

→ x² + y² = 9xy - 2xy

→ x² + y² = 7xy (Hence ,Proved).