answer the question kkkkkkk
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area of trapazium =1/2(ab+cd)ac
=1/2(3.5+5.5)*3.5=15.75cm^2
area of quadrant whose radius is given 3.5cm
pi*r^2 ÷4
={22/7(3.5*3.5)}÷4
=9.625
area of remaining portion will be=area of trapazium - area of quadrant
15.75-9.626 =6.125cm^2
this is the required ans
hope it helps!!!
=1/2(3.5+5.5)*3.5=15.75cm^2
area of quadrant whose radius is given 3.5cm
pi*r^2 ÷4
={22/7(3.5*3.5)}÷4
=9.625
area of remaining portion will be=area of trapazium - area of quadrant
15.75-9.626 =6.125cm^2
this is the required ans
hope it helps!!!
Answered by
2
it is right I am also 8th class it's in my notes
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