Answer the question no. 10 pls
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In triangle ABD and CBE
AB=BC(given)----(1)
✓B=✓B(common)---(2)
✓A=✓C(given)
divided by 2 on both sides
both sides✓A/2=✓B/✓BAD=✓BCE(proved above)--(3)
From equation 1,2,3By AAS congruency property triangle ABD congruent to triangle CBE.
Hope it helps you.
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