Question

Solve this answer:

In the detailed method

5/√5-√5

​

Answer 1

$\Large\mathcal{\underline{\underline{Answer:-}}}$

$\Large\bold→\infty$

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$\small\mathfrak{\underline{\underline{Step-By-Step\:Explanation:-}}}$

$= > \frac{5}{ \sqrt{5} } - \sqrt{5}$

Multiplying and diving by $\sqrt{5}$

$= > \frac{5}{ \sqrt{5} } - \sqrt{5} \times \frac{ \sqrt{5} }{ \sqrt{5} }$

$= > \frac{5}{ \sqrt{5} } - \frac{5}{ \sqrt{5} }$

Taking Lcm

$= > \frac{5 - 5}{ \sqrt{5} }$

$= > \frac{0}{ \sqrt{5} }$

$\Large\bold\Rightarrow\infty$

Hence, the number tends to infinity

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INFINITY —

Infinity is a concept for unbound values for example counting, you cannot find the end of it. It continues. So the values like this which do not have end are refered as they have infinte values. It is represented by '∞' which is larger than any real number.

Answer 2

$\frac{5}{ \sqrt{5 - \sqrt{5 } } } \\ = \frac{5( \sqrt{5} + \sqrt{5} }{( \sqrt{5} - \sqrt{5)} ( \sqrt{5} + } \sqrt{5)} \\ = \frac{5 \sqrt{5} + 5 \sqrt{5} }{5 - 5 } \\ = 5 \sqrt{5 } + 5 \sqrt{5}$