answer the question please in the given picture
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Let percentage of 1st isotope be x %, then percentage of second will be (100-x)%.
Relative Atomic Mass = Ist Isotope×its % + 2nd isotope×its %
10.8 = 10 × x/100 + 11 × (100-x)/100
10.8 = 10x+1100-11x/100
1080 = 1100-x
x = 20%
So percentage of B-10 is 20% and percentage of B-11 is 80%.
Relative Atomic Mass = Ist Isotope×its % + 2nd isotope×its %
10.8 = 10 × x/100 + 11 × (100-x)/100
10.8 = 10x+1100-11x/100
1080 = 1100-x
x = 20%
So percentage of B-10 is 20% and percentage of B-11 is 80%.
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