Question

to what temp must a gas at 300 k be cooled down in order to reduce its volume to1/3 of its original volume pressure constant

Answer 1

Hello Rohit,
question-given
 t₁=300k,let v₁=V ∴v₂=V/3,t₂=?
according to Charles' Law 
v₁/t₁=v₂/t₂
subsituting values,
V/300=V/3/t₂
=V/300=V/3t₂
=3t₂=300
∴t₂=100
the given gas should be cooled to 100k such that volume becomes 1/3rd

Answer 2

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