Question

Answer the question with explanation and describe your answer.​

Answer 1

$\huge\mathfrak\red{Answer}$

WHAT IS WORK DONE?

IN PHYSICS WE HAVE SOME BASIC QUANTITY NAMELY DOT PRODUCT ,CROSS PRODUCT WHICH IS REQUIRED TO EXPLAIN WORK DONE.

DOT PRODUCT OF TWO VECTOR

WHEN TWO VECTOR SAY "a" AND "b" INCLINED AT AN ANGLE "∆" WITH EACH OTHER THAN DOT PRODUCT IS THE PRODUCT OF COMPOSITION OF ONE VECTOR OVER THE OTHER.

MATHEMATICAL

a.bCos∆= Dot product of a and b

SIMILARLY

Work done is the dot product of force with displacement.

Work Done=f.s Cos∆

F is force

s is DISPLACEMENT

∆ is angle between them

ANOTHER IMPORTANT

POINT TO REMEMBER

WORK DONE ON OR BY ANY SYSTEM =ENERGY WASTED OR GENERATED BY THE SYSTEM

POTENTIAL ENERGY

THE ENERGY TO DO WORK GENERATED BY THE SYSTEM DUE TO ITS POSITION IS KNOWN AS POTENTIAL ENERGY

INTERESTING POINT

IT IS IMPOSSIBLE TO CALCULATE POTENTIAL ENERGY OF THE SYSTEM WE CAN CALCULATE POTENTIAL DIFFERENCE OF THE SYSTEM ONLY.

$mass = 15kg \\ height = 1.5m \\ \\ potential \: difference = mgh \\ potential \: difference = 15 \times 1.5 \times </strong><strong>1</strong><strong>0</strong><strong> \\ potential \: difference =</strong><strong>2</strong><strong>2</strong><strong>5</strong><strong> joules$

Answer 2

Answer:

The work done by him on luggage is 225 Joules.

Explanation:

Given :

Mass of the luggage is 15 kg.

Constant of gravity is 10 m/s²

Height is 1.5 m.

To Find :

The work done by him on luggage.

Solution :

So,

We have,

• M = 15 kg
• G = 10 m/s²
• H = 1.5 m

We know that :

$\bigstar\;\boxed{\sf Work = Mass \times Gravity \times Height.}}$

Now,

$\sf\\ \\\implies 15\times10\times1.5\\ \\ \\ \implies 225\;J.$

∴ The work done by him on luggage is 225 Joules.

$\rule{300}{1.5}$

• Explanation of the Question :

Question :

A porter lifts a luggage of 15 kg from the ground and puts it on his head 1.5m above the ground. Calculate the work done by him on the luggage.

So,

In question :

A porter lifts a luggage of 15 kg.

You can see here it state that the Mass of the luggage is 15 kg.

Now, You can see I've 15 kg as mass.

Next,

A porter lifts a luggage of 15 kg from the ground and puts it on his head 1.5m above the ground.

Now, We already have  M = 15 kg.

So, Here It state that 1.5m above the ground. Which is giving us height.

Now, you have,

• M = 15 kg .
• H = 1.5 m.

We have the constant of gravity 10 m/s².

Now you have :

• M = 15 kg .
• H = 1.5 m.
• G = 10 m/s²

Now, Simply subsitute them is the formula of work.

Because, It is given that we have to find work done.