Question

answer the question with explanation and I'll mark you as a brainliest and if you answer me with random things I'll report you :)

Answer 1

Answer:

• Speed₁ = 1500 m
• Time₁ = 300 sec
• Initial Velocity₂ = 2 m/s
• Acceleration = 2.4 m/s²
• Final velocity = 10 m/s
• Time₂ = ?

$\displaystyle\underline{\bigstar\:\textsf{According to the given Question :}}$

• The formula average speed,time and distance is, $\sf{Avg \ Speed = \dfrac{Total \ Distance}{Total \ Time}}$

$\displaystyle\sf :\implies Avg \ Speed = \dfrac{Total \ Distance}{Total \ Time}$

$\displaystyle\sf :\implies Avg \ Speed = \dfrac{1500}{300}$

$\displaystyle:\implies\underline{\boxed{\textsf{ \textbf{Avg Speed = 5 m/s}}}}$

• In case 2 the initial velocity is 2 m/s and the final velocity was 10 m/s with an acceleration of 2.4 m/s². So then we shall find the Time taken and we can do so with the help of the first equation of motion

$\displaystyle\sf \dashrightarrow v = u+at$

$\displaystyle\sf \dashrightarrow 10 = 2+2.4\times t$

$\displaystyle\sf \dashrightarrow 10-2 = 2.4t$

$\displaystyle\sf \dashrightarrow 8 = 2.4t$

$\displaystyle\sf \dashrightarrow \dfrac{8}{2.4} = t$

$\displaystyle\sf \dashrightarrow\underline{\boxed{\textsf{ \textbf{Time = 3.4 s}}}}$