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Answer 1

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We know..

$= > focal \: \: length(f) = \frac{1}{power(d)} \: \: \: m$
Now,

Focal length (f)
$= \frac{1}{5} = 0.2m = 20 \: \: cm$
Now since focal is positive so.. Its a convex lens.
And

For a convex lens, magnified image is formed when,

1)

When object is placed between optical centre and focal length, then we get a virtual, erect and magnified image.

So, in case of object kept at 18 cm, we get a magnified image.

2)

When object is placed between focal length (f) and radius of curvature (2f), we get a real, inverted and magnified image.

So, in case of object at 30 cm, we get a magnified image.

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