Physics, asked by Anonymous, 11 months ago

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Answered by sg2544
11
hello mate!.....


7) WE KNOW》

weight =  \frac{mass \: of \: body}{acceleration \: due \: to \: gravity}
soooo

a) weght is decreaced

b)weight some wt increased

c)no change.

9) we know......


a =  \frac{ - gm}{r {}^{2} }  \\  \\
M= mass

r= radius.

a=acceleration from gravity

sub the values u get G value.


hope it helps u
Answered by Deepsbhargav
32
[8]

Given:

=> m1= 10kg

=> m2= 20kg

=> G= 6.673 x 10^-11Nm^2kg^-2

=>r = 5
________

=> F = Gm1m2/r²

=> F = (6.673 x 10^-11 x 10 x 20)/5²

=>F = 6.673 x 8 x 10^-11

=> F = 53.3 x 10^-11 N
_______________[ANSWER]

====================================!

[9]



=> g = F / m = G.Mm / (Rm)²

=> g = (6.67×10^-11)(7.4×10^22 kg) /(1740×10³m)²

=> g = 0.284×10^5m/s²

=> g = 2.84×10³ m/s²
_____________[ANSWER]

====================================

[10]

=> h= 3200km = 3200000m = 3.2 x10^6

=> R= 6400km = 6400000m = 6.4 x 10^6

=> g= 9.8m/s^2

______

We know that-

=> g'= g[R^2/(R+h)^2]

=> g' = 9.8(40.96 x 10^12/92.16 x 10^12)

=> g' = 9.8 x 4/9

=> g' = 4.355m/s^2 ~ 4.4m/s^2
__________[ANSWER]

=====================================

[11]

=> weight of body on earth = 120 N

=> 120 = m x 9.8

=> m = 120/9.8

=> m = 12.24 kg

=> weight on moon = mass x acceleration due to gravity

=> weight on moon = 12.24 x 1.63

=> weight on moon = 19.9 N
______________[ANSWER]

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