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Hey mate ☺
No, g(x) is not the factor of p(x) as when these are divided they leave remainder as 2 ..
so, this shows that g(x) is not the factor of p(x)
Hope it helps you ☺✌✌
No, g(x) is not the factor of p(x) as when these are divided they leave remainder as 2 ..
so, this shows that g(x) is not the factor of p(x)
Hope it helps you ☺✌✌
shaaran40:
this is perfect answer
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No, g(x) is not the factor of p(x) as when these are divided they leave remainder as 2 ..
so, this shows that g(x) is not the factor of p(x)
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