Question

answer them all pls​

Answer 1

QUESTION 1-

ABCD is a parallelogram.

In triangle ADB and triangle DCB,

Opposite sides of parallelogram are equal so,

AB=CD and AD=BC.

Opposite angles of a parallelogram are equal so,

angle DAB= angle DCB

Therefore, triangle ADB is congruent to triangle DCB (by SAS)

                                                                   Hence Proved.

QUESTION 2-

(As shown in image)

Source- https://www.topperlearning.com/answer/prove-that-angles-opposite-to-equal-sides-of-a-triangle-are-equal/6hlb56nqq

Question 3-

In triangle ABO and triangle DCO,

angle DOC = angle BOA (vertically opposite angles)

angle DCO= angle BAO (right angles)

and AB=CD (given)

Therefore, triangle ABO and DCO are congruent by AAS.

                                                             Hence proved.