The sum of three no in ap is -3 & their product if 8 find A.P.
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↪️↪️Let a - d , a , a + d are thre numbers are in AP.
↪️Given sum of three numbers in an AP is= -3 .
✴️ (a + d) + (a) + (a - d) = -3
✴️ 3a = -3
✴️ a = -1
↪️Product of 3 numbers = 8
➡️ (a - d)a(a + d ) = 8
➡️a( a² - d²) = 8
➡️ -1( 1 - d²) = 8
➡️ 1 - d² = -8
➡️d² = 1 + 8
➡️ d = ± 3
✴️ then -1 - 3, -1 , -1 + 3 or -1 + 3 , -1 , - 1 -3.
↪️↪️↪️the numbers in AP are ⤵️⤵️
➡️ ➡️ ➡️ -4 , -1 , 2
↪️Given sum of three numbers in an AP is= -3 .
✴️ (a + d) + (a) + (a - d) = -3
✴️ 3a = -3
✴️ a = -1
↪️Product of 3 numbers = 8
➡️ (a - d)a(a + d ) = 8
➡️a( a² - d²) = 8
➡️ -1( 1 - d²) = 8
➡️ 1 - d² = -8
➡️d² = 1 + 8
➡️ d = ± 3
✴️ then -1 - 3, -1 , -1 + 3 or -1 + 3 , -1 , - 1 -3.
↪️↪️↪️the numbers in AP are ⤵️⤵️
➡️ ➡️ ➡️ -4 , -1 , 2
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