answer these 3 question
correct and clear answer will be marked as brainlist
Answers
35.) BC+CD=BD
BC=BD-CD
let BC be x meter
BD=(40+x)meter
In triangle ABD
AB/BD= tan45⁰
AB=40+x------------(i)
In triangle ABC
AB/x = tan60⁰
AB=root3x----------(ii)
comparing (i) and (ii)
40+x-root3x
40=root3x-x
40/root3=x-x
(23.09=AB) or (40/root3meter)
BC=40root3×root3
= 40/root3×root3
=40meter
36) Given the tower is 30m away from point A.
Given angle of elevation of top of tower is 30.
Let the height of tower be x
tan30=BC/AB
=1/root3=x/30
x=30/root3×root3/root3
=(30×root3)/3
threfore ,,, height of tower =10root3=10×1.732
=17.32
37) Here AC is a ladder and AB is the height of wall.
BC=2m
Now, tan60=AB/BC
root3=AB/2
therefore, AB=2 root3 metre