Question

answer these four questions

Answer 1

hey ___________________________

here is your answer↓

→ refer to the attachment

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hope it helps!!

Answer 2

Hii friend,

X-1 = 0

X = 1

Putting the value of X in,

P(X) = X²+X+K

P(1) = (1)² + 1 + K

= 1 + 1 + K = 0

K = -2

(2) P(X) = 2X²+KX+✓2

P(1). = 2 × (1)² + K × 1 + ✓2

= 2 +k + ✓2

K = -2-✓2

(3) P(X) = KX²-✓2X+1

P(1) = K × (1)² - ✓2 × 1 + 1

= K -✓2+1

K = ✓2-1

HOPE IT HELPS!!!!