Question

Answer these question

Answer 1

As we are given

S1=n

S2=2n

S3=3n

Now substitute the value in

S3=3(S2+S1)

So we get,

3n=3(2n-n)

3n=3(n)

3n=3n

Hence.

LHS=3n

And RHS=3n

LHS=RHS

Hence proved.

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