Question

answer these question class 10 chapter introduction to trigonometry...​

Answer 1

Step-by-step explanation:

${cot}^{2} (90 - \alpha ) = {tan}^{2} \alpha \\ {cot}^{2} 64 = {cot(90 - 26}^{2} \\ {cot}^{2} (90 - 26) = {tan}^{2} 26$

according to trigonometric identities

${sec }^{2} \alpha - {tan}^{2} \alpha = 1$

$so \\ {sec}^{2} 26 - {tan}^{2} 26 = 1$

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