Math, asked by suvasuvi, 11 months ago

ANSWER THESE QUESTIONS......
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Answered by Madhu7409
0
hey there...

(A-2I) (A-3I)=0

A^2 - 3A- 2A + 6I = 0

A^2 - 5A + 6I = 0

A^2 = A.A [ 4. 2. ] [ 4. 2. ]
[ -1. x. ] [-1. x. ]

= [16-2 8+2x]
[-4-x x^2-2]

= [ 14 8+2x] + [ -20 -10 ] + [ 6 0 ]
[ -4-x x^2-2] [ 5 -5x] [ 0 6 ]

= [ 0 2x-2 ] [0 0]
[ -x +4 x^2-5+4] = 0 [0 0]

= -x + 1 = 0
x=1

= 2x-2=0
x=1

= x^2 -5x+4=0
(x-1) (x-4) = 0
x=1 is possible

x= 4 is not possible.

therefore x = 1.

I hope it will help you...
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