Question

Answer these questions
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Plz answer 8

Answer 1

Hii friend,

Solution:- P(X) => 5X²-4-8X => 5X²-8X-4


=> 5X²-10X+2X-4

=> 5X(X-2)+2(X-2)

=> (X-2) (5X+2)


=> (X-2) = 0 OR (5X+2) = 0


=> X = 2 OR X = -2/5

Therefore,

2 and -2/5 are the zeros of the given polynomial.


Let Alpha = 2 And Beta = -2/5


Sum of zeros = (Alpha + Beta) = 2+(-2/5) => 2-2/5 => 10-2/5 => 8/5 = -(Coefficient of X/Coefficient of X².

And,


Product of zeros = (Alpha × Beta) => 2 × -2/5 => -4/5 => Constant term/Coefficient of X².




HOPE IT WILL HELP YOU...... :-)