Question

Answer This and become the Brainliest :)

Question. 6!! Thanks

Answer 1

Consider it as AP.
t1=1^3-3^1=1-3= -2
t2=2^3-3^2=8-9=-1
t3=3^3-3^3=27-27=0

a=-2, d=-1
Find the sum by putting these values in this formula.
$s = n \div 2 \times (2 \times a + (n - 1) \times d)$
Then you will get the sum of n terms of the series.