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Hi there!
Given Eqn. :- px² -2√5 px + 15 = 0
Here,
a = p , b = -2√5 , c = 15
→ For Equal roots :-
D = 0
b² - 4ac = 0
( -2√5 p )² - 4 × p × 15 = 0
20p² - 60p = 0
20p (p - 3)= 0
Therefore,
20p = 0 or ( p - 3 ) = 0
p = 0 or p = 3
Hence, The required answer is :- p = 0 or p = 3
Hope it helps! :)
Given Eqn. :- px² -2√5 px + 15 = 0
Here,
a = p , b = -2√5 , c = 15
→ For Equal roots :-
D = 0
b² - 4ac = 0
( -2√5 p )² - 4 × p × 15 = 0
20p² - 60p = 0
20p (p - 3)= 0
Therefore,
20p = 0 or ( p - 3 ) = 0
p = 0 or p = 3
Hence, The required answer is :- p = 0 or p = 3
Hope it helps! :)
kartik338:
Thnx a lot can you solve other questions of math u can get in from my profile please do it
sure! uh can also follow :)
have u find tge questions
have u find the questions
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