Question

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Answer 1

$12x \div 100 + 10y \div 100 = 130$
..........( 1 )
$10x \div 100 + 12y \div 100 = 134$
..........( 2 )
On Solving, We get : -
$12x + 10y = 13000$
$10x + 12y = 13400$
On Adding, we get
$22 \: ( \: x \: + \: y \: ) = 26400$
$x + y = 1200$
...........( 3 )

On Subtracting , We get
$2 \: ( \: x \: - \: y \: ) = - 400$
$x - y = - 200$
............( 4 )

On Adding (3) & (4) we get,
$2x = 1000$
$x = 500$
$and \: y = 1200 - 500 = 700$
Therefore, on 12% & 10% interest he invested 500 & 700 ₹ respectively !

Hope This Helps !