Question

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Answer 1

Explanation:

f = -12cm

u = -36cm

h1= 2cm

Position of the image

1/v=1/f-1/u

Therefore 1/v= -1/12 - (-1/36)

=-1/12 + 1/36

Take LCM

=-3+1/36

=-2/36

=-1/18

Therefore v=-18

Nature of image:---Real and Inverted

Size of image

h2/h1=-v/u

h2/2=-(-18/-36)

h2/2=-(18/36)

h2=-18*2/36

h2=-1

Answer 2

Answer:

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