Question

Answer this...⬇️

In the adjacent figure ABCD is a parallelogram ABEF is a rectangle show that ∆AFD~∆BEC

Answer correctly

By Aryabhatta or brainly teachers​

Answer 1

In given figure ABCD is a parallelogram and ABEF is a rectangle .

Then AF=BE (opposite side of rectangle ).....................(1)

And AD=BC (opposite side of parallelogram )...................(2)

∠AFE=∠AFD=∠BEF=∠BEC=90

0

(angle of rectangle ABEF)....................................(3)

ΔAFD and ΔBEC

∠AFD=∠BEC=90

0

..(From 3)

AF=BE (From 1)

AD=BC (From 2)

∴ΔAFD≅ΔBEC

Answer 2

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