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given :-
length of the hypotenuse = 5cm
and length of one of the side of the triangle = 3cm
by Pythagoras theorem, we know that hypotenuse² = base² + perpendicular²
let the other two sides be a and b.
⏩ hypotenuse² = a² + b²
⏩ 5² = 3² + b²
⏩ 25 = 9 + b²
⏩ 25 - 9 = b²
⏩ 16 = b²
⏩ b = √16
⏩ b = 4cm
hence, the length of other side is 4cm.
given :-
length of the hypotenuse = 5cm
and length of one of the side of the triangle = 3cm
by Pythagoras theorem, we know that hypotenuse² = base² + perpendicular²
let the other two sides be a and b.
⏩ hypotenuse² = a² + b²
⏩ 5² = 3² + b²
⏩ 25 = 9 + b²
⏩ 25 - 9 = b²
⏩ 16 = b²
⏩ b = √16
⏩ b = 4cm
hence, the length of other side is 4cm.
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