determine the 25th term of an ap whose 9th term is -6 and the common difference is 5 by 2
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9th term is -6 n d = 5/2
a + (9-1)*5/2 = -6
a + 8*5/2 = -6
a + 20 = -6
a = -26
so 27th term-
a + (27-1) 5/2
= -16 + 26*5
= -16 + 65
= (-16+65)
= 49
thus the 27th term is 49
a + (9-1)*5/2 = -6
a + 8*5/2 = -6
a + 20 = -6
a = -26
so 27th term-
a + (27-1) 5/2
= -16 + 26*5
= -16 + 65
= (-16+65)
= 49
thus the 27th term is 49
anumanikandan:
i asked 4 25ty term
25th*
Common difference is given 5/4, first term would come out to be -16,hence 25th term would be 14
how come 14?
14 is wrong??
its 44
Question u have written different and question written in Attachment is different,i have solved question written in attachment,which will result into answer of -16+(25-1)(5/4)=14,if i am taking d=5/4 as you written than answer would be 44 like -16+(25-1)*(5/2)= -16+60 = 44.
sry and tq
*If i am taking d=5/2 as u written
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