Math, asked by Anonymous, 11 months ago

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Answered by Anonymous
6

Hope It helps!!!!!!!!!

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Anonymous: Thanks a lot.....
Anonymous: yup!
ty009: Nice ans.
Answered by clockkeeper
2

y =  log_{e}( {e}^{x} (  { \frac{x - 2}{x + 2} )}^{ \frac{3}{4} }  )  \\ y = x +   \frac{3}{4} ln((x - 2))  -  \frac{3}{4}  ln(x + 2)  \\  \frac{dy}{dx}  = 1 +  \frac{3}{4} ( \frac{1}{x - 2}  -  \frac{1}{x + 2} ) \\  \frac{dy}{dx}  = 1 +  \frac{3}{4} ( \frac{x + 2 - x + 2}{ {x}^{2} - 4 } ) \\  \frac{dy}{dx}  = 1 +  \frac{3}{ {x}^{2} - 4 }  \\   \frac{dy}{dx}  =   \frac{ {x }^{2} - 4 + 3 }{ {x }^{2} - 4 }  =  \frac{ {x}^{2} - 1 }{ {x}^{2}  - 4}

hope it helps

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ty009: Nice ans.
clockkeeper: tks.(^~^)
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