Question

Answer this.


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Answer 1

Explanation:

m×am = n × an

m {a+(m-1) d } = n { a+(n-1) d}

am + m² d-md = an +n² d-nd

am-an= m²d+n²d -nd +md

a (m-n)=d ( n²-m²+m-n)

a (m-n)=d { (n-m) ( n + m) + m-n}

a (m-n)=d (m-n) { - 1 ( n+m)+1}

a=d (-n-m+1).. (1)

to prove ;(m+n)th terms is zero (m+n)thterms=a+(n-1)d

Answer 2

Answer:

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