Question

answer this one also....

Answer 1

zero is the right answer of this question

Answer 2

Given : (x/y) + (y/x) = -1.

= > (x^2 + y^2)/xy = -1

= > x^2 + y^2 = -xy

= > x^2 + y^2 + xy = 0 -------- (1)

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We know that a^3 - b^3 = (a - b)(a^2 + ab + b^2).

Given :

= > (x^3 - y^3)

= > (x - y)(x^2 + y^2 + xy)

= > (x - y)(0) [From (1)]

= > 0.

Therefore, x^3 - y^3 = 0.

Hope this helps!