Question

Answer this please because very important question not only for me more than 1 Million+ students all over world.

Alevel question mathematics trigonometry,

PROVE THAT, [1+tan^2 (45-A)]/[1-tan^2 (45-A)] =cosec2A

Answer 1

Answer:

Step-by-step explanation:

Please mark my answer brainlist.

Answer 2

Formulas:

1. (1 - tan^2A)/(1 + tan^2A) = cos2A

2. (1/sinA) = cosecA

Given:

$\frac{1 + tan^2(45 - A)}{1 - tan^2(45 - A)}$

$=> \frac{1}{\frac{1 + tan^2(45 - A)}{1 - tan^2(45 - A)}}$

$=> \frac{1}{cos2(45 - A)}$

$=> \frac{1}{cos(90 - 2A)}$

$=> \frac{1}{sin2A}$

$=> \boxed{cosec2A}$

Hope it help you!