Answer this please....by solving......very uegent....
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1) Partial pressure of He is 0.33 atm.
2) Partial pressure of O2 is 0.52 ATM.
2) Partial pressure of O2 is 0.52 ATM.
selena17:
what is As,??
i need the formula and technique of solving this
P1×V1=P2×V2
just this
Wait for a while.........please
okk
P1×V1=P2×V2
P1×V1=P2×V2
P1=Pressure of he in 200ml vessel
V1=Volume of He initially
P2=Final partial pressure of He
V2=Final volume of vessel.
Therefore,
0.66×200
=>P2×400
=>P2=0.32atm
Hence, partial pressure of he is 0.32
Next initially O2 is present at 0.52 atm of 400ml and then it is placed on 400ml vessel .
Hence the partial pressure of O2 is 0.52.
P1=Pressure of he in 200ml vessel
V1=Volume of He initially
P2=Final partial pressure of He
V2=Final volume of vessel.
Therefore,
0.66×200
=>P2×400
=>P2=0.32atm
Hence, partial pressure of he is 0.32
Next initially O2 is present at 0.52 atm of 400ml and then it is placed on 400ml vessel .
Hence the partial pressure of O2 is 0.52.
Is this useful...
oh thank you soooo much
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