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Volume of cuboid (V)=abc.
Surface area of cuboid(S)=2 (ab+bc+ca).
On dividing these two,we get,
S/V=2 (ab+bc+ca)/abc
=2 (ab/abc+bc/abc+ca/abc)
=>S/V=2 (1/c+1/a+1/b)
Therefore,
1/V=2/S (1/a+1/b+1/c).
Hence,proved.
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