answer this plz........
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total no. of possible outcomes=8
the favourable outcome is only one head(H)
no. of favourable outcomes =1
required probability P(T)= 1/8
the favourable outcome is only one head(H)
no. of favourable outcomes =1
required probability P(T)= 1/8
Nityanoel:
but how the total oucomes become 6
Total Outcomes are 8
3 times a coin is tossed.. for one time tossed we get 2 outcomes
p(e) is 2/8
No not 3 times its 3 coins
sorry it 8
hey how to ans this que
no three coins are tossed just once only
Mark me as brainliest plz
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Hey Mate here is your answer ⤴ ⤴
Hope it helps ✌ ✌ ✌ ✌
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is this answer correct
yeah......its correct
r u sure?
yes
ok fine
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