Question

answer this plz guyz ​

Answer 1

E)= five answer
2 is multiplied by 2 added in 1

Answer 2

EXPLANATION.

If the straight lines.

⇒ 2x - y + 3 = 0. - - - - - (1).

⇒ x - y + 2 = 0. - - - - - (2).

⇒ ax - 2by + c = 0. - - - - - (3).

are concurrent,

Then the family of lines : 3ax - 2by + c = 0 is concurrent at.

As we know that,

Solving equation (1) and (2), we get.

⇒ 2x - y + 3 = 0. - - - - - (1).

⇒ x - y + 2 = 0. - - - - - (2).

⇒ x + 2 = y. - - - - - (2).

Put the value of equation (2) in equation (1), we get.

⇒ 2x - (x + 2) + 3 = 0.

⇒ 2x - x - 2 + 3 = 0.

⇒ x + 1 = 0.

⇒ x = - 1.

Put the value of x = - 1 in equation (2), we get.

⇒ y = x + 2.

⇒ y = - 1 + 2.

⇒ y = 1.

Put both the value of x = - 1 and y = 1 in equation (3), we get.

⇒ ax - 2by + c = 0. - - - - - (3).

⇒ a(-1) - 2b(1) + c = 0.

⇒ - a - 2b + c = 0.

⇒ c = a + 2b.

Family of lines : 3ax - 2by + c = 0.

Put the value of c = a + 2b in equation, we get.

⇒ 3ax - 2by + a + 2b = 0.

⇒ 3ax + a + 2b - 2by = 0.

⇒ a(3x + 1) + b(2 - 2y) = 0.

⇒ x = - 1/3  and  y = 1.

Points are : [-1/3,1].